Is simple harmonic motion an application of circular motion? If so, how are they related? Examining the velocity, acceleration, and position of a weighted spring as it oscillates will reveal any relationships. Tracking the velocity of the weighted spring as it vibrates through several cycles produces a curve that has precisely the same shape as a sinusoidal curve, so-called because it is like the graph of the sine function in trigonometry. That is, simple harmonic motion is sinusoidal in nature.
Simple harmonic motion is also based on uniform circular motion. Note that the x-axis on the illustration shows radian units. Why is this? The circumference of a circle is equal
to radians; and for each cycle of the weighted spring, it completes one circle.
If you would like to know more about radian measure than just click Applied Mathematics 30 – Cyclic Patterns ; then click “Start” beside Graphing Cyclic Data. (You may need to obtain a username and a password from your teacher.)
Reopen the Simple Harmonic Motion: Weighted Spring simulation, if necessary, and observe uniform circular motion and simple harmonic motion at the same time by doing the following:
SC 8. Describe one similarity and one difference between the velocity vector on the reference circle and the velocity vector on the weighted spring.
SC 8. The velocity vectors are similar in their vertical magnitude. They are different in that the reference circle has both vertical and horizontal velocity while the weighted spring only exhibits vertical velocity.
Without changing any of the settings in the simulation, turn on the graphing function (), and select “Velocity,” as illustrated below. Then close vectors popup by clicking on the “Close” button. Close the graphing popup by pressing the “Graphs” button ().
Review the questions below so you know what to look for, and click “Play.”
Remember to submit the answer to TR 2 to your teacher as part of your Module 7: Lesson 1 Assignment.
TR 2.
Set up the simulation as indicated in the following diagram by clicking the “Vectors” button () popup. Choose the “position” and “acceleration at origin” selections; then click the “Vectors” button to close the popup. Next, click the graphing function (), and select the “Position” and “Acceleration” functions, as illustrated below. Then click the “Graphs” button to close the popup.
Press “Play,” and observe the orientation of the acceleration and displacement vectors.
SC 9. Explain how the orientation of the acceleration and displacement is related to the negative sign in
SC 9. The acceleration and displacement are always pointing in opposite directions, so the force and displacement are also in opposite directions. The opposite directions are indicated mathematically using the negative in
How can you calculate the maximum speed of a mass on a spring, and where does the maximum occur? Read pages 366 to 372 in your textbook to find out.
SC 10. Complete question 1 of “Practice Problems” on page 372 of the textbook.
SC 11. Complete question 2 of “Practice Problems” on page 372 of the textbook.
SC 10.
m = 0.724 kg
k = 8.21 N/m
the displacement of the mass at that acceleration (x)
Choose the positive direction to be to the right. Then the acceleration will have a negative value. Use Hooke’s law and Newton’s second law to find the displacement.
The displacement of the mass is 0.362 m [right].
SC 11.
m = 50.0 g
k = 4.00 N/m
A = 1.12 m
the maximum speed of the mass
Convert the mass to kilograms. The maximum speed can be found from the maximum kinetic energy. The maximum kinetic energy will equal the maximum potential energy, which occurs at the maximum displacement, the amplitude.
The maximum speed of the mass is 10.0 m/s.
Remember to submit the answer to TR 3 to your teacher as part of your Module 7: Lesson 1 Assignment.
TR 3.
A 250-g object hangs from a spring and oscillates with an amplitude of 5.42 cm. If the spring constant is 48.0 N/m, determine the acceleration of the object when the displacement is 4.27 cm [down].
If the spring constant is 48.0 N/m, determine the maximum speed. Tell where the maximum speed will occur.