Read pages 153 to 157 of your textbook.
SC 2.
Go to page 158 of your textbook and complete question 9(a) of “3.3 Check and Reflect.”
SC 2.
mA = 4.0 kg, where mA is the mass of the oak block
mB = 2.0 kg, where mB is the mass hanging down
a = ?
Equivalent system
is equal to the friction force on .
is equal to the gravitational force on .
= +
The acceleration of the system is 1.30 m/s2 to the right.
If you have ridden an elevator in a tall building, you have no doubt felt an apparent change in your weight. You feel slightly heavier as the elevator starts upward and a little lighter as it slows to a stop at an upper floor. When you ride back down, you feel lighter when the elevator starts down and slightly heavier as it slows and stops at a lower floor. Can Newton’s laws explain this? Investigate how the motion of an elevator relates to Newton’s laws in the following lab.
This lab simulates the motion of an elevator. It helps you apply free-body analysis and Newton's second law to determine the relationship between apparent weight, normal force, and actual weight.
You can learn more about the simulation and how to use it by reading Show Me found at the top of the simulation screen.
How do you determine the acceleration of an elevator?
Before starting the lab, check your understanding for the precise meaning of these terms.
Quantity | Symbol | SI Unit |
weight | N | |
mass | m | kg |
acceleration due to gravity | m/s2 | |
* The acceleration due to gravity at Earth's surface is approximately –9.81 m/s2. |
Remember to submit the answer to LAB 4 to your teacher as part of your Module 3: Lesson 5 Assignment.
LAB 4. Using the definitions above, complete the following calculations and explanations.
Open the Elevator simulation; then continue with the procedure. You may be required to login with a username and a password. Contact your teacher for this information.
SC 3. Answer the following questions based on your observation of the passenger weight and normal force on any elevator trip.
SC 3.
Set up the following parameters on the elevator applet:
The elevator will accelerate, coast, and then come to a stop. This represents a typical elevator trip. Observe carefully what happens to the weight (W) and normal force (N) vectors that are drawn on the simulation during each phase of the trip. Once the elevator has stopped, you may wish to reset the elevator and observe the motion again.
SC 4. Use the terms greater than, equal to, or less than to compare the size of the normal force when the elevator is at rest to the size of the normal force as the elevator
SC 4.
Remember to submit the answer to LAB 5 to your teacher as part of your Module 3: Lesson 5 Assignment.
LAB 5. The apparent weight of the passenger equals the magnitude of the normal force acting on the passenger. Use the terms greater than, equal to, or less than to compare the passenger's weight when the elevator is at rest to the apparent weight when the elevator
SC 5. Based on your observations and experience riding in an elevator, which force, weight or apparent weight, do you feel when the elevator
SC 6. Complete the table by drawing the free-body diagrams in each phase of the elevator trip. Indicate the relative magnitude (size) of the normal force and the weight on each diagram.
SC 7. The net force acting on the occupant is the sum of all force acting on the occupant. This is described by
a. Rewrite the equation using Newton's second law, where
(______) = () + (______) (2)
b. Manipulate the equation in SC 7.a. in terms of the normal force ().
= (______) – (______) (3)
SC 5.
a. apparent weight
b. weight
c. apparent weight
SC 6.
a.
b.
c.
SC 7.
a. () = () + ()
b. = () – ()
The equation = () – () can be used to determine the apparent weight of a passenger when the acceleration () of the elevator is known.
For example, what is the apparent weight of a 55.0-kg person on an elevator that is accelerating upward at 3.00 m/s2?
SC 8. An elevator ride consists of three distinct phases characterized by the acceleration of the elevator itself: accelerating upward, coasting/resting, and accelerating downward. Complete the following chart. Calculate the normal force using equation = () – () and the values for m = 60.0 kg and = +4.0 m/s2 for each phase of the elevator trip. The value of is –9.81 m/s2. You will need to set the mass of the passenger and the acceleration () of the elevator in the applet. Note that the direction and magnitude of the acceleration will be different in each phase of the trip and that they are indicated in the following table. Verify your answers on the simulation using the normal force value from the scale reading shown in the upper left corner of the applet.
Accelerating Upward (+) |
|
Coasting/Resting (constant speed) |
|
Accelerating Downward (–) (slowing down) |
SC 9. Consider the three distinct phases of an elevator ride:
For two of the phases of the ride, scale readings indicate apparent weight. For the remaining phase, the reading is actual weight.
SC 8.
Accelerating Upward (+) |
|
Coasting/Resting (constant speed) |
|
Accelerating Downward (–) (slowing down) |
SC 9.
To reinforce what you have learned in the elevator lab so far and to prepare for your next assignment question, read “Applying Newton’s Second Law to Vertical Motion” on pages 151 to 153 of your textbook.
Remember to submit the answer to LAB 6 to your teacher as part of your Module 3: Lesson 5 Assignment.
LAB 6. Use the simulation for assistance in answering the following questions.
The acceleration of an elevator can be determined using free-body analysis and Newton's second law.
The observed acceleration (a) is related to the net force by Newton's second law.
N is the normal force, which is equal in magnitude to the passenger’s apparent weight.
W is the actual weight of the passenger, produced by the effect of the gravity acting on a mass: W = mg