Read pages 159 to 161 of your textbook. Look for significant differences between Newton’s third law and the two laws you previously studied.
SC 1. Complete the following sentence by filling in the blank. In Newton’s third law, the two forces not only act in different directions, they also act on different __________.
SC 1. Complete the following sentence by filling in the blank. In Newton’s third law, the two forces not only act in different directions, they also act on different objects.
What happens when forces are exerted between objects that are separated and do not touch each other? Read “Action-Reaction Forces Acting on Objects in Contact” and “Action-Reaction Forces Acting on Objects Not in Contact” on pages 161 to 163 of your textbook. Look for significant differences between the two situations.
SC 2. What are two situations where action-reaction forces act on objects that are not in contact?
SC 2. Other answers are possible, but two situations where action-reaction forces act on objects that are not in contact include the following:
Have you ever moved an object without touching it by pushing on other objects that were in contact with it? How are Newton’s laws involved in what happens? Read “Applying Newton’s Third Law to Situations Involving Frictionless Surfaces” and “Applying Newton’s Third Law to Situations Involving Friction” on pages 164 to165 of your textbook to see how the calculations are done. You will learn more in Module 3: Lesson 4 about the free-body diagrams used in these examples.
SC 3.
SC 3.
What are the action-reaction pairs in propeller aircraft and rockets? Read pages 166 and 167 of your textbook. Look for significant differences between propeller aircraft and rockets.
SC 4.
SC 4.
Re-open the Momentum Conservation simulation, if necessary. Then complete the following questions.
TR 1. Two hockey players are standing at centre ice. One player with a mass of 75.0 kg pushes the other player with a mass of 95.0 kg. Which player will move away with a greater acceleration? Why? Verify your answer using the applet.
Remember to submit the answers to TR 2 and TR 3 to your teacher as part of your Module 3: Lesson 2 Assignment.
TR 2. Two basketball players run into each other. Player 1, with a mass of 55.0 kg, experiences a –15.6 m/s2 acceleration. If player 2 has a mass of 48.5 kg, what acceleration did she experience immediately following the collision?
TR 3. Complete the following table. The first row has been completed as an example.
Action |
Action Force |
Reaction Force |
A bullet is fired from a gun by the expanding gases. |
expanding gases pushing on the bullet |
bullet pushing back on the expanding gases |
A volleyball is served. |
player's hands exerting a forward force on the ball |
|
The Moon orbits Earth. | moonward pull of the Moon acting on Earth | |
A firewoman opens the fire hose, and water sprays forward. |
||
A sprinter’s shoe hits the ground. |
SC 5. Solve problem 8 of “3.4 Check and Reflect” on page 168 of the textbook.
SC 5.
8. (a)
mX = 10 kg mY = 5.0 kg = 36 N [right]
the action-reaction forces of the blocks on each other ( and )
Only the horizontal forces need to be considered. Let the direction to the right be positive. Calculate the acceleration of the two-block system. Then calculate the force necessary to accelerate block Y, which will be .
The positive value indicates the force is to the right. By Newton’s third law, the force of block Y on block X will be equal in magnitude but in the opposite direction or left.
The force of block X on block Y is 12 N [right], and the force of block Y on block X is 12 N [left].
8.(b)
mX = 10 kg mY = 5.0 kg = 36 N [right] = 8.0 N
= 4.0 N
the action-reaction forces of the blocks on each other ( and )
Only the horizontal forces need to be considered. The direction of the forces of friction will be left because that is opposite to the direction of travel. Calculate the acceleration of the two-block system. Then calculate the net force that accelerates block Y.
The positive value indicates the force is to the right. However, block X must exert an extra 4.0 N to overcome the force of friction on block Y. Therefore, the force of block X on block Y will be (8.0 N + 4.0 N) or 12 N. By Newton’s third law, the force of block Y on block X will be equal in magnitude but in the opposite direction or left.
The force of block X on block Y is 12 N [right], and the force of block Y on block X is 12 N [left].
Watch the video titled Newton’s Laws Part 4, which explains the significance of Newton’s laws.
Remember to submit the answers to TR 4, TR 5, and TR 6 to your teacher as part of your Module 3: Lesson 2 Assignment.