Module 2—Motion in Two Dimensions

Read

Read “Objects Launched at an Angle” on pages 108 to 110 of your textbook. As you read, look for the answers to the next Self-Check question.

Self-Check

SC 1.

1. If a projectile returns to the same height from which it was launched, what is the Δdy?
   
   
2. Knowing the answer to SC 1.a., what formula can you use to find Δt?

SC 2. Re-open the Projectile Motion: One Ball simulation. Position the ball at (x, y) = (10.0 m, 0.0 m), and set the initial velocity as 25.0 m/s at an angle (θ) of 50.0° relative to the positive x-axis.

(x, y) = (10.0 m, 0.0 m)     (vi, θ) = (25.0 m/s, 50.0°)

Using the appropriate kinematics equations and initial values, calculate the position and velocity at t = 3.00 s. After you have completed your calculations, verify your answers by entering the launch speed and direction in the simulation and stepping through the motion to 3.00 s.

1. horizontal component of the initial velocity
2. vertical component of the initial velocity
3. horizontal velocity at 3.00 s
4. vertical velocity at 3.00 s
5. horizontal position at 3.00 s
6. vertical position at 3.00 s

Module 2: Lesson 4 Assignment

Remember to submit the answer to TR 1 to your teacher as part of your Module 2: Lesson 4 Assignment.

Try This

TR 1. Using the Projectile Motion: One Ball simulation, position the ball at
(x, y) = (0.0 m, 0.0 m) and set the initial velocity as 25.0 m/s at an angle (θ) of 65.0° relative to the positive x-axis.

(x, y) = (0.0 m, 0.0 m)     (vi, θ) = (25.0 m/s, 65.0°)

Using the appropriate kinematics equations and initial values, determine the position and velocity at t = 2.40 s. Enter the launch speed and direction on the simulation, and step through the motion to 2.40 s to verify your answers.

1. horizontal component of the initial velocity
2. vertical component of the initial velocity
3. horizontal velocity at 2.40 s
4. vertical velocity at 2.40 s
5. horizontal position at 2.40 s
6. vertical position at 2.40 s

Physics 20 © 2008 Alberta Education