In Try This 3 you may have noticed that the column and the total number of possible permutations are the same. This formula provides you with a way to calculate the permutations without the need for tree diagrams or lists. In the next scenario you will see how blanks or the formula can be used to solve a problem.
Consider the following scenario.
Six people are boarding an empty bus that has 30 seats. In how many different ways may the people be seated?
Solving the Problem Using Blanks
If you would like to solve this scenario by drawing blanks, draw your blanks for the elements that are most restricted. In this case there are fewer people on the bus than there are seats, so draw the blanks to represent each person. Then fill in the blanks with the number of seats the people may choose from.
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Since the first person who gets on the bus has 30 seats to choose from, 30 is placed in the first blank. Now one seat is taken, so the second person has 29 seats to choose from, and so on.
When you complete this solution by filling in all six blanks, you get 30 × 29 × 28 × 27 × 26 × 25, or 427 518 000 ways.
Solving the Problem Using the Permutations Formula
In this example, n is 30 and represents the total number of seats; r is 6 and represents the number of people who choose a seat. You are finding the number of ways of choosing 6 items (r) from 30 items (n), which can be represented by
When you are presented with permutation questions, it is important to be able to identify n (the total number of objects there are to select from) and r (the number of objects being selected each time). Some questions will require you to do a little word deciphering to find these values. You can practise this deciphering as you solve the Self-Check problems.