Module 6: Exponents and Logarithms

 

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In Try This 1 you were solving logarithmic equations. A logarithmic equation is an equation in which there is a logarithm of a variable. You may have found that when a logarithmic equation is in the form logc L = logc R, where the left side and right side each contain a single logarithm with the same base, the logarithms can be removed.


textbook

Read “Link the Ideas” on page 406 of the textbook. Notice that a proof of the preceding property is provided.

 


In Try This 2 you will use this property: if logc L = logc R, then L = R. You will explore how to solve a more difficult logarithmic equation.

 

Try This 2

 

Use the logarithmic equation log2 (x − 2) + log2 (x + 1) = 2 for the following questions.

  1. Using a law of logarithms, write the left side of the equation as a single logarithm.
  2. Use your answer from question 1 and write the equation with the single logarithm on the left side and “equal to 2” on the right side. Change the equation to exponential form and solve for x.
  3. Write the right side of the equation as a single logarithm. This logarithm should have the same base as the logarithm on the left side and the logarithm should equal 2.
  4. Use your answers from questions 1 and 3 to solve the equation for x.
  5. How could you check to see if your answers are correct?
  6. Are all of your solutions correct? Explain your answer.
  7. Explain why the logarithm of a negative number is undefined.

course folder Save your responses in your course folder.

If logc A = logc B, then A = B.
log2 2 = 1, log2 ? = 2, log2 8 = 3
Try to use the product law: logb M + logb N = logb (M × N).