Module 3: Polynomial Functions

 

You should have concluded that x = 7, 4, 2, and −1 are solutions to the equation. The whooping crane population will be 45 after 2, 4, and 7 years. Since Isabel is looking forward and not backward, −1 is not used.

 

Many steps were used to solve this problem. Here is a summary of how to solve polynomial equations.

 

Example Mathematical Justification
Solve 2x3 + 3x2 − 17x + 7 = −5. Your teacher asked you to solve this.
2x3 + 3x2 − 17x + 12 = 0 Add 5 to both sides to create an equivalent equation where the zero-product property can be used.
The factors of 12 are ±1, ±2, ±3, ±4, ±6, ±12. The integral zero theorem says to check factors of the constant term using the factor theorem.

Graph f(x) = 2x3 + 3x2 − 17x + 12:

 

This is the graph of f of x equals 2x cubed + 3x squared minus 17x + 12.

Rather than testing all of the factors of 12, graph the function and look for x-intercepts, because x-intercepts correspond to factors.

Test for a factor of x + 4.

 

 

It appears that x = −4 is an x-intercept. This would correspond to a factor of x − (−4), which is normally written as x + 4.

 

The factor theorem says that xa is a factor of P(x) if P(a) = 0.

Perform (2x3 + 3x2 − 17x + 12) ÷ (x + 4).

 

 

 

2x3 + 3x2 − 17x + 12 = (x + 4)(2x2 − 5x + 3)

x + 4 is a factor, so divide by this factor to determine another factor.

 

This example uses synthetic division, but you can use long division (from Lesson 2) if you prefer.

2x2 − 5x + 3 = (2x − 3)(x − 1)

 

2x3 + 3x2 − 17x + 12 = (x + 4)(2x − 3)(x − 1)
The quadratic can also be factored.
(x + 4)(2x − 3)(x − 1) = 0 Rewrite the equation using this equivalent factored form so the zero-product property can be used.

x + 4 = 0

 

2x − 3 = 0

 

x − 1 = 0
Apply the zero-product property.
 Solve. These are the solutions to the original equation.