f(x) = −(x + 3)3(x − 4)
Step 1: Determine the end behaviour by looking at the degree of the polynomial and the sign of the leading coefficient.
There are four factors containing x; therefore, the expanded form of the polynomial is of degree 4. The degree of the polynomial is even and the polynomial has a negative leading coefficient. This means the graph will start in quadrant 3 and end in quadrant 4.
Step 2: Factor the polynomial if it is not given in the problem.
This question is already factored.
Step 3: Determine the x-intercepts by looking at the factors of the polynomial.
The x-intercepts are x = −3 and 4.
Step 4: Determine the y-intercept by substituting zero into the function.
The y-intercept occurs at the point (0, 108).
Step 5: Determine the nature of the x-intercepts (whether there is a sign change) by looking at the multiplicity of the polynomial’s factors.
The factor (x + 3) has a multiplicity of 3, so the graph will “flatten out” and cross the x-axis at x = −3. The factor (x − 4) has a multiplicity of 1, so the graph will cross the x-axis at x = 4.
Step 6: Draw a smooth curve through the x- and y-intercepts.