Module 2: Lesson 3

 

Self-Check 3
  1.  Question 15 on page 98 of the textbook
    1.  

      1. In order to solve the question graphically, certain information needs to be substituted into the formula as shown:

         

         

        There are two methods that can be used to solve this equation.

        Method 1: Use a System of Two Functions

        Graph the following functions, and determine the x-value of the intersection point of the two functions.

         


         
        This is a graph of two functions. The first is distance equals 3.69 times begin square root 20 divided by velocity squared end square root. The second function is distance equals 3.2. The intersection point of the two functions is labelled at (5.16, 3.2).

        To the nearest metre per second, the landing velocity is 5 m/s.

        Method 2: Use a Single Function


        Rearrange the equation  so that the equation equals zero.

         


        Graph the function , and then determine the x-intercept of the graph.

         
        This is a graph of the function distance equals 3.69 times begin square root 20 divided by velocity squared end square root subtract 3.2. The x-intercept is labelled at (5.16, 0).

        To the nearest metre per second, the landing velocity is 5 m/s.

      2. In order to solve the question graphically, certain information needs to be substituted into the formula:

         

         

        There are two methods that can be used to solve this equation.

        Method 1: Use a System of Two Functions

        Graph the following functions, and then determine the x-value of the intersection point of the two functions.

         


         
        This shows the graphs of two functions. The first function is distance equals 3.69 times begin square root of mass divided by 4 end square root. The second function is distance equals 16. The intersection point of the two functions is labelled at (75.21, 16).

        To the nearest tenth of a kilogram, the maximum mass of the parachutist would be 75.2 kg.

        Method 2: Use a Single Function

        Rearrange the equation  so that the equation equals zero.

         


        Graph the function , and then determine the x-intercept of the graph.

         
        A graph of the function distance equals 3.69 times begin square root mass divided by 4 end square root subtract 16 is shown. The x-intercept of the function is labelled at (75.21, 0).

        To the nearest tenth of a kilogram, the maximum mass of the parachutist would be 75.2 kg.



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